According to Wein’s Law, The peak wavelength of radiation emitted is determined by the temperature of the emitter according to the following equation. λmax=2900/Twhere T is the temperature of the emitter in degrees Kelvin (water freezes at 273 degrees K, 0 degrees Celsius and 32 degrees Fahrenheit). NASA’s Cassini space probe has made several fly-bys of Saturn’s moon Titan, the only moon with an atmosphere. Here is your problem. Given that Earth’s average temperature is 15 degrees Celsius and Titan’s temperature is -180 degrees Celsius, calculate who has the longer peak wavelength (don’t worry about having the correct units) and what the ratio is between the longer and shorter wavelength.
from the Wein's law
λmax=2900/T
on the earth
T = 15+273 = 288 K
λmax=2900 um .K/288 K = 10.06 um
on the Titan’s
T = -180+ 273 =93 K
λmax=2900 um .K/93 K = 31.18 um
Titan has longer wavelength
ratio = 31.18/10.06 =3.09
According to Wein’s Law, The peak wavelength of radiation emitted is determined by the temperature of...