Question

QUESTION 11 How many nitrate ions are present in 25.0 mL of 0.150 M copper(ll) nitrate solution? e a 0.00750 ions b.4.52 x 1021 ions 12.01 x 1023 ions 2.26 x 1021 tons

Answer 1

lly a mole Cu (NO) contains a mole Nog ion- 1000 ml te solution contains = 0.15 mole Ce (NO3)2 : 25 ml - 10-15 425) mole = 0.00375 mble So, nitrate (NO) ion present = 2x Cu(NO3)2 = (2x0.00375 mole = 0.0075 mole A mole No = 6:023x10 23 o no. of ions. 0.0075 mole No = (6.023 x 1023 0.0075) n. = 4.52 x 1021 eons. Hence, option b) is correct. 12) NOS 25+1=6( frigonal structures) - VSEPR. The resonance structure indicates that at the both the N-0 bonds are same and bond orders are in intermediate between single and double bond. So, (b) es correct