The data file below contains a sample of customer satisfaction
ratings for XYZ Box video game system. If we let µ denote
the mean of all possible customer satisfaction ratings for the XYZ
Box video game system, and assume that the standard deviation of
all possible customer satisfaction ratings is 2.64:
Ratings |
39 |
45 |
38 |
42 |
42 |
41 |
38 |
42 |
46 |
44 |
40 |
39 |
40 |
42 |
45 |
44 |
42 |
46 |
40 |
47 |
44 |
43 |
45 |
45 |
40 |
46 |
41 |
43 |
39 |
43 |
46 |
45 |
45 |
46 |
43 |
47 |
43 |
41 |
40 |
43 |
44 |
41 |
38 |
43 |
36 |
44 |
44 |
45 |
44 |
46 |
48 |
44 |
41 |
45 |
44 |
44 |
44 |
46 |
39 |
41 |
44 |
42 |
47 |
43 |
45 |
(a) Calculate 95% and 99% confidence intervals
for µ. (Round your answers to 3 decimal
places.)
95% confidence interval for µ is | [, ]. |
99% confidence interval for µ is | [, ]. |
(b) Using the 95% confidence interval, can we be
95% confident that µ is at least 42 (recall that a very
satisfied customer gives a rating of at least 42)?
(Click to select)NoYes , because if we are 95% confident that
the interval contains μ, and the entire interval is (Click to
select)belowabove 42, then we are 95% confident that μ is greater
than 42.
(c) Using the 99% confidence interval, can we
be 99% confident that µ is at least 42?
(Click to select)NoYes , because if we are 99% confident that the interval contains μ, and the entire interval is (Click to select)abovebelow 42, then we are 99% confident that μ is greater than 42.
(d) Based on your answers to parts b
and c, how convinced are you that the mean satisfaction
rating is at least 42?
(Click to select)Very confidentNot confident based on the 99% confidence interval being (Click to select)belowabove 42.
Sample size, n = 65
σ = 2.64
Sample mean calculates, x̅ = 42.9538
a) 95% confidence interval:
Two tailed critical value, zcrit = NORM.S.INV(0.05/2) = 1.96
Lower Bound = x̅ - zcrit*σ/√n =
42.312
Upper Bound = x̅ + zcrit*σ/√n =
43.596
99% confidence interval:
Two tailed critical value, zcrit = NORM.S.INV(0.01/2) = 2.576
Lower Bound = x̅ - zcrit*σ/√n =
42.110
Upper Bound = x̅ + zcrit*σ/√n =
43.797
--------------------
(b) Yes , because if we are 95% confident that the interval contains μ, and the entire interval is above 42, then we are 95% confident that μ is greater than 42.
(c) Yes , because if we are 99% confident that the interval contains μ, and the entire interval is above 42, then we are 99% confident that μ is greater than 42.
(d) Very confident based on the 99% confidence interval being above 42.
The data file below contains a sample of customer satisfaction ratings for XYZ Box video game...
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Recall that "very satisfied" customers give the XYZ-Box video game system a rating that is at least 42. Suppose that the manufacturer of the XYZ-Box wishes to use the random sample of 70 satisfaction ratings to provide evidence supporting the claim that the mean composite satisfaction rating for the XYZ-Box exceeds 42. (a) Letting µ represent the mean composite satisfaction rating for the XYZ-Box, set up the null hypothesis H0 and the alternative hypothesis Ha needed if we wish to...
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Sample Data Sample Data Hour Sample Taken Hour Sample Taken 1 4 5 X 1 3 1 42 2 3 4 5 6 2 39 36 25 60 28 53 22 56 41 34 43 45 59 42 36 40 45 39 48 26 42 34 61 48 45 29 3 31 61 38 40 54 26 38 42 37 41 53 37 47 41 37 29 20 26 43 38 33 37 37 35 33 36 41 25 37...
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