Question

1. Write the IUPAC of the following structures : (12 points) HOCCHCOCI 6) (CN)2 CHOH i dob dolina HOA bubong noista d) locale abybobo T CHE O=0 HO C-CH2 CH -CH N HON

Answer 1

1.

a) 3-oxopropanoyl chloride

Reason;

COCl is highest priority and suffix is 'oyl chloride' there are 3 carbon so propan as parent chain. prefix of aldhehyde group is oxo and it is at 3 position so 3-oxopropanoyl chloride.

b) 2-hydroxypropanedinitrile

Reason; Nitrile group has highest priority and alcohol is lowest priority so numbering done from CN. Parent chain is of 3 carbon including 2 nitrile group so propanedinitrile.

c) 4-hydroxy-3-methoxybenzaldehyde

Reason; the parent chain is benzene and the highest priority is aldehyde group so benzaldehyde and numbering done from aldhehyde so at 3 position is methoxy and 4 is hydroxy group.

d) 3-amino-4-((1-methoxy-1-oxo-3-phenylpropan-2-yl)amino)-4-oxobutanoic acid

Reason; the highest priority is carboxylic acid so numbering is done from that point. At 3 position is amino and at 4 position there is one amino group & one propanyl chain attached so in propanyl chain at 3 position is phenyl ring. In this propanyl chain numbering is done from carbonyl carbon.