When 2 lines are perpendicular, the product of their slopes = -1. Therefore m1 x m2 = -1
The slope of line (5/4)x - y = 6 is m1 = 5/4
Therefore (5/4) x m2 = -1
m2 = -4/5.
This line passes through the point (0,0), therefore by the skope point method, we get
y - 0 = (-4/5) * (x - 0)
y = -(4/5)x
We need the equation of the line in the STandard Form = Ax + By + C = 0 form
Cross multiplying, 5y = -4x
Therefore 5y + 4x = 0 (Option 2)
10. Write an equation of a line in standard form for the given conditions. passes through...
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Find an equation of the line that passes through the point (4, 2) and is perpendicular to the line 2x + 5y 6 = 0 Need Help? Talk to a Tutor Read It Find an equation of the line that passes through the point (4, 2) and is perpendicular to the line 2x + 5y 6 = 0 Need Help? Talk to a Tutor Read It
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