Question

scale : I mm = 0.120 m/s Example Homework #5.1 W, = 144 rad's 92 = 1000 rad/s2 Scale: Imm= 12.0 m/s2 Find az, a4 19 31.8 25.4R 2 3 88.9 W2 25.4 4 U V = (0₂B) Wz = 0.0318(144) = 4.58 m/s Vg to Vala ✓ Vc to Volc % ☺ Volen imm = 0.120 m/s

Answer 1

= 29-50 r2 = 31-8mm = 88.9 mm 31.8mm 88.9 mm OL > R25-4mm 25.4 mm C 142 Ple C= 25-4 mm Given Wq = 164 radls Py. Ginen 42 = 1000 radls. Wyz 50-4 radls (cow) Wya 189 radls ((w)

The angle between the crank and horizontal is found by using velocity diagram. In velocity diagram, the angle between the horizontal and crank velocity is 60.5 degrees. SInce crank velocity and crank are perpendicular to each other, therefore the crank angle is 29.5 degrees.

Acceleration @s), Tw, 31-3 (44*65444•g mol,- : (а) 2 654-чоҷ8 г.- 31800 mmiga (en) - Y, ҡ, 3-8 х (ooo 2 * bв): 31-3 m) - @cle), Tw.“. 88-9x 50-4° = 215-20 m), (ООО lacleu). (ас), Ко- 25.4 x164- 125-449 ml. lood acceleration diagram 1mm 12m),- 1 :. \ав) = GS- Чоч% с ящ hosb-h9 12. (%) = 3 - 2.6 mm = в'e (@els), - 15:22 225-82 с 13:318 mm. (ас), - Bв!" +L5:449 60-454 mm= O₂c² - -

54.95mm 18.818mmy 2.65mm

60.454mm 54.95mm 57.467mm 60.454mm 18.8 18mm 2.65mm 18.104mm

from diagram O₂ B' = 54.95mm O2, P4 BB 2.65mm BB" = 18.818mm. < Puch 60-454mm B BV B BTC = 18-104mm CWC = 57.467mm. ("c= Pue'= 60.454mm (act = 57.467812 c'c'= (act = 689.604 m/s 181104x122 220-84 8mls? 689.604 m/s? 19cIB) Bl'c = @(16)Ł acle)+7 du = lacht १५ dan 25-4x1013 :. du= 27149.764 radly = 220-848 88.9x103 &z= 2484.229 rad/s2