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Exercise 4: Answer both (a) and (b) for full credit. Consider the following LP problem: Maximize Profit Objective Function: $

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Answer #1

a) The graph of the inequalities is plotted as shown

200 (0.100) -200 200 300 400- -100 200The optimal solution is the point of intersection shown on the graph

(X_1,X_2)=(0,100)

b) If profit of X_1 is raised to $3 per unit, the profit maximising objective function becomes

\$3X_1+\$1X_2

The constraints however remain same.

The objective function is also depicted on the graph below along with the constraints

200. (0.100) -300 -200 - 100 200 300 400 - 100 -200.The optimal solution remains at (X_1,X_2)=(0,100) . Hence optimal solution is not changed.

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