Question

H Collision Between Two Balls Part A Two identical steel balls, each of mass 3.20 kg, are suspended from strings of length 31.0 cm so that they touch when in their equilibrium position. We pull one of the balls back until its string makes an angle 0 = 52.0° with the vertical and let it go. It collides elastically with the other ball. How high will the other ball rise? m п Submit Answer Tries 0/5 Part B Suppose that instead of steel balls we use putty balls. They will collide inelastically and remain stuck together after the collision. How high will the balls rise after the collision? Submit Answer Tries 0/5

Answer 1

initial height of ball 1

cos x = ( L - h) / L

cos 52 = ( 31 - h) / 31

h = 11.91 cm

since the collision is elastic in nature so ball 2 qill also reach to the sa. e height as ball 1

h = 11.91 cm

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bl final velocity of ball1 just before impact

u = sqrt (2 gh)

u = sqrt ( 2 * 9.8* 0.1191)

u = 1.528 m/s

now using conservation of momentum

m1 u = ( m1 + m2) v

3.2* 1.528 = 2* 3.2* v

v = 0.764 m/s

using 3rd equation of motion

h = v^2/ 2g

h = 0.764^2 / (2* 9.8)

h = 2.948 cm

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