Question

Wednesday Homework Problem 3.10 If a metal cube with sides of length lcm is charged with a "D" cell battery, a charge of 1.3 x 10-12C is developed. If this cube is then placed in a spherical object with radius 50.0cm. What is the electric flux out of the sphere? Select One of the Following (a) 2.7 x 10-15N㎡/C (b) 4.6 × 10-14N㎡/C (c)1.7 x 10-4Nm2/C (d) 5.2 x 10-3Nm2/C (e) 0.15Nm2/C

Please justify the answer you choose, thank you!

Answer 1

Given that The metal cube with sides of length is 1 cm Charge inside the cub = 1.3 times 10^-12 C charge enclosed in sphere = charge inside the cube q = 1.3 times 10^-12 C The electric flux out of the sphere phi = q/epsilon_0 since from Gauss law where epsilon_0 permittivity of free space epsilon_0 = 8.85 epsilon 10^-12 c^2/Nm^2 substitute value to get phi = q/epsilon_0 \r\n phi = 1.3 times 10^-12 C/8.85 times 10^-12 c^2/Nm^2 phi = 0.1468 Nm^2 phi = 0.15 Nm^2/c The electric flux out of the sphere phi = 0.15