Homework Answers
As we are looking at a lower bound here and we are given the output for a t - test here for testing whether the difference in the population means between the two populations is equal to 0 or greater than 0, therefore the null and the alternative hypothesis here are given as:
These are the required set of hypothesis here.
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F) Given the Minitab output below: Two-Sample T-Test and Cl: height, gender Two-sample T for height...
Two-Sample T-Test and CI: height, gender
Two-sample T for height gender N Mean StDev SE Mean male 19 5.73 0.51 0.117 female 24 5.25 0.47 0.096 Difference = mu (male) - mu (female) Estimate for difference: 0.48 90% lower bound for difference: 0.283 T-Test of difference = 0 (vs >): T-Value = 3.17 P-Value = 0.002 DF = 18 Fill in the blanks: Ho: Ha: Type of test: t- test – SRS, Normal ?=?=.05 t-value = P-value: look up on your t-table Decision: Conclusion:
Quiz 6: The Minitab output for the packing time example is as follows: Two-Sample T-Test and...
Quiz 6: The Minitab output for the packing time example is as follows: Two-Sample T-Test and CI: New machine, Old machine Two-sample T for New machine va 0ld machine StDev 42.140 0.683 0.750 SE Mean 0.22 0.24 N Mean New machine old machine 10 43.230 10 Difference u (New machine) H (0ld machine) Estimate for difference: -1.090 T-Test of difference 0(vs ): T-Value -3.40 P-Value 0.003 DE= 18 Both use Pooled StDev 0. 7174 Test the variances of this test.
The Minitab output for the packing me u p Two-Sample T-Test and CI: New machine, Old...
The Minitab output for the packing me u p Two-Sample T-Test and CI: New machine, Old machine TWO-sample for New machine vs old machine New machine old machine N 10 10 Mean St Dev SE Mean 42.140 0.683 0.22 43.230 0.750 0.24 (old machine) Difference = (New machine) - Estimate for difference: -1.090 TONE OL GILLorence (VS Both use pooled stDev = 0.7174 -value =-3.40 P-value = 0.003 DF - 18 - Test the variances of this test.
The MINITAB printout shows a test for the difference in two population means. Two-Sample T-Test and...
The MINITAB printout shows a test for the difference in two population means. Two-Sample T-Test and CI: Sample 1, Sample 2 Two-sample T for Sample 1 vs Sample 2 N Mean StDev SE Mean Sample 1 6 28.00 4.00 1.6 Sample 2 9 27.86 4.67 1.6 Difference = mu (Sample 1) - mu (Sample 2) Estimate for difference: 0.14 95% CI for difference: (-4.9, 5.2) T-Test of difference = 0 (vs not =): T-Value = 0.06 P-Value = 0.95...
Stat 210 Quiz 6: The Minitab output for the packing time example is as follows: Two-Sample...
Stat 210 Quiz 6: The Minitab output for the packing time example is as follows: Two-Sample T-Test and CI: New machine, Old machine Two-sample for New machine vs old machine Mean St Dev SE Mean 42.140 0.683 0.22 43.230 0.750 0.24 10 10 New machine old machine (old machine) Difference = u(New machine) - Estimate for difference: -1.090 18 -value = -3.40 P-Value - 0.003 DY 1 st OE CELOzence (VSP Both use pooled St Dev=0.7174 - Test the variances...
Stress between males and females *Note: alpha = .001 1 t-Test: Two-Sample Assuming Unequal Variances Female...
Stress between males and females
*Note: alpha = .001
1 t-Test: Two-Sample Assuming Unequal Variances Female Male 4 Mean 5 Variance 6 Observations 7 Hypothesized Mean Difference 3.655737705 3.52857143 1.296174863 1.12236025 70 61 8 df 9 t Stat 10 P(T-t) one-tail 11 t Critical one-tail 12 P(T<-t) two-tail 13 t Critical two-tail 124 0.658596658 0.255687918 3.157259054 0.511375836 3.370720124 Student Survey Data (2 Sample t-test) 1. Test Decision & Basis 2. Interpretation of Test Decision:
t-test: two-sample assuming equal variances Subject ID Height Mean 9.9 68.85 Variance 39.0421053 35.0815789 Observations 20...
t-test: two-sample assuming equal variances Subject ID Height Mean 9.9 68.85 Variance 39.0421053 35.0815789 Observations 20 20 Pooled Variance 37.0618421 Hypothesized Mean Difference 0 df 38 t Stat -30.621066 P(T<=t) one-tail 1.0856E-28 t Critical one-tail 1.68595446 P(T<=t) two-tail 2.1711E-28 t Critical two-tail 2.02439416 From your results, please report the following: Variable 1 Mean: Variable 2 Mean: Two-tailed p-value: Is your p-value significant? (alpha=0.05) If your results are significant/not significant, what can you conclude from your data? (i.e. is there a...
is that enough for you Two-Sample T-Test and CI: 2011, 2012 Two-sample T for 2011 vs...
is that enough for you
Two-Sample T-Test and CI: 2011, 2012 Two-sample T for 2011 vs 2012 2011 2012 N 75 93 Mean 6.466 6.604 St Dev 0.352 0.398 SE Mean 0.041 0.041 Difference=mu (2011) -mu (2012) Estimate for difference: -0.1376 95% CI for difference: (-0.2535, -0.0217) T-Test of difference=0 (vs not =) : T-Value = -2.34 P-Value=0.020 DF = 166 Both use pooled StDev=0.3782 Manutan International S.A. is a specialist mail-order business providing industrial and office equipment and supplies...
Q2) Independent-Samples t-Test (15 points total) Help with H, I, J, K, L please! In a...
Q2) Independent-Samples t-Test (15 points total) Help with H, I, J, K, L please! In a research project, researchers collected demographic and health data from a sample of elderly residents in the community. To examine any possible gender differences in their sample, they want to see if the females and the males differ significantly on the education level (number of years of formal schooling). The researchers are not predicting any direction in the possible gender differences so the hypotheses should...
Quiz 6: The Minitab output for the packing time example is as follows: Two-Sample T-Test and CI: New machine, Old machine Two-sample T for New machine va 0ld machine StDev 42.140 0.683 0.750 SE Mean 0.22 0.24 N Mean New machine old machine 10 43.230 10 Difference u (New machine) H (0ld machine) Estimate for difference: -1.090 T-Test of difference 0(vs ): T-Value -3.40 P-Value 0.003 DE= 18 Both use Pooled StDev 0. 7174 Test the variances of this test.
The Minitab output for the packing me u p Two-Sample T-Test and CI: New machine, Old machine TWO-sample for New machine vs old machine New machine old machine N 10 10 Mean St Dev SE Mean 42.140 0.683 0.22 43.230 0.750 0.24 (old machine) Difference = (New machine) - Estimate for difference: -1.090 TONE OL GILLorence (VS Both use pooled stDev = 0.7174 -value =-3.40 P-value = 0.003 DF - 18 - Test the variances of this test.
Stat 210 Quiz 6: The Minitab output for the packing time example is as follows: Two-Sample T-Test and CI: New machine, Old machine Two-sample for New machine vs old machine Mean St Dev SE Mean 42.140 0.683 0.22 43.230 0.750 0.24 10 10 New machine old machine (old machine) Difference = u(New machine) - Estimate for difference: -1.090 18 -value = -3.40 P-Value - 0.003 DY 1 st OE CELOzence (VSP Both use pooled St Dev=0.7174 - Test the variances...
Stress between males and females
*Note: alpha = .001
1 t-Test: Two-Sample Assuming Unequal Variances Female Male 4 Mean 5 Variance 6 Observations 7 Hypothesized Mean Difference 3.655737705 3.52857143 1.296174863 1.12236025 70 61 8 df 9 t Stat 10 P(T-t) one-tail 11 t Critical one-tail 12 P(T<-t) two-tail 13 t Critical two-tail 124 0.658596658 0.255687918 3.157259054 0.511375836 3.370720124 Student Survey Data (2 Sample t-test) 1. Test Decision & Basis 2. Interpretation of Test Decision:
is that enough for you
Two-Sample T-Test and CI: 2011, 2012 Two-sample T for 2011 vs 2012 2011 2012 N 75 93 Mean 6.466 6.604 St Dev 0.352 0.398 SE Mean 0.041 0.041 Difference=mu (2011) -mu (2012) Estimate for difference: -0.1376 95% CI for difference: (-0.2535, -0.0217) T-Test of difference=0 (vs not =) : T-Value = -2.34 P-Value=0.020 DF = 166 Both use pooled StDev=0.3782 Manutan International S.A. is a specialist mail-order business providing industrial and office equipment and supplies...
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