Question

1 3 5 6 P(a) 0.03 0.14 0.31 0.33 0.15 0.04 11. P(2S< 5) is about (a) 0.22 (b) 0.78 (c) 0.17 (d) 0.50 (e) 0.52 12. The mean of the random variable r is about 3.55 (b) 0.59 (c) 3.00 (d) 4.12 (e) 3.96 13. The standard deviation of the random variable a is about (a) 1.25 (b) 1.12 (c) 13.85 (d) 3.55 (e) 12.60

Answer 1

P(2HS) Answer: P(2HS) is about P(2)+ P(3)+ PI4) 0.14 t 0.31 + 0.33 P(2H5) = 0.78

12The mean of the ranclem vanable e is about Answers mean- Elx) Edepl) PW+2 P(2)+3P(3)+4P14)+5AS)+6 P6) 10.03)+ 2l0.14)+3(0.31)+4(0. 33)+S(o.15) +6(0.04) Elx) 3.SS mean

132 The standaorl deviaticn of the rendam vamable ris about Answer Elx2) - E2PI) 12 P)+22 Pl2) +32A3)+4?P14)t5 PS)+6Pl6) 1 l0.03)+4(0.14)+9(6.31)+16(0.33) +25(6.15)+360.0o E(xリニ13.85 stanclaazl dleviation (x)- Ex2) -E(x)2 V13.85 3.5572 VI.2475 standanel dleviation ( 1.12

Guestion-23 GNen maagin ot e E=2% = 0.02 Sample parpcatim-p19 -0.19 A 95%% confidemie leael of significanie 1-0.95-0.05 axitical value level Zo.o5 2 20.025 2. 2-1.96 using 7-table 2 1 2d12 sample size= h 1.96 (o.19)(1-0.19) 0.02 1478.0556 149 Sample size= n