Question

Java

Convert the QuartsToGallons program to an interactive application. Instead of assigning a value to the number of quarts, accept the value from the user as input.

Given program:

public class QuartsToGallons {
public static final int QUARTS_IN_GALLON = 4;

public static void main(String[] args) {
int quartsNeeded=18;
// finding required quarts
System.out.println("A job that needs " + quartsNeeded + " quarts requires " + (quartsNeeded/QUARTS_IN_GALLON) + " gallons plus "
+ (quartsNeeded % QUARTS_IN_GALLON) + " quarts");
}
}

Answer 1

import java.util.Scanner;

public class QuartsToGallons {
    public static final int QUARTS_IN_GALLON = 4;

    public static void main(String[] args) {
        Scanner scanner = new Scanner(System.in);

        int quartsNeeded = scanner.nextInt();

        // finding required quarts
        System.out.println("A job that needs " + quartsNeeded + " quarts requires " + (quartsNeeded/QUARTS_IN_GALLON) + " gallons plus "
                + (quartsNeeded % QUARTS_IN_GALLON) + " quarts");
    }
}