Question

Translate the following C code to MIPS assembly code. Use a minimum number of instructions.

Register allocations

- i $s0

- j $s1

- base of A[] $s2

- base of B[] $s3

2)

A[3] = B[i] + B[j];

3)

i = 0;

while (j != A[i]) {

i++;

}

Answer 1

Li to; 12 SiL sti, $50, 2 sl st2, 4s1, 2 Libet aded tt, $t, $s3 add dt, sto, s3 Lw 9u, 0CED Lw stz, ecdt adel tt, Sty tt2 adel $to, sto, 352 Sw $t, OCsto
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