see experiment 1 and 3:
[H2] doubles
[NO] is constant
rate becomes 4 times
so, order of H2 is 2
see experiment 1 and 2:
[H2] is constant
[NO] becomes 0.0030/0.0020 = 1.5 times
rate becomes (1.8*10^-4)/(1.2*10^-4) = 1.5 times
so, order of NO is 1
overall order = 2 + 1 = 3
Answer: 3
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