Question

Set 3: Resistor Loaded Emites Re Transistor Pataneters VBELON) O.7V -W RB Vec VCELGAT) 0.3 RE Given Va3V, A Vc= 1ov, Rg-600 k2, Re=8k2, Rez K Determine iB, E, ic, and Vee 2) Design he citcuit above forward VB8= 3 V, Vec= 12V, V=4V, the So that itoperates Following Conditians the active with mode and 3Giren Vss4V, Ve 12 V, Rg ="10k2, Re = 2 k2, and RE4K Deternine he ope iste of the transistos

Answer 1

[I_E = (1 + beta) I_B I_C = beta I_B] using K V L in Base loop - V_BB = I_B R_B + V_BE + (1 + beta) I_B R_E 3 = I_B . 600 + 0.7 + (1 + 125) . 4 I_B I_B = 2.0833 mu A I_C = beta I_B = 125 times 2.0833 I_C = 0.2604 m A I_E = (1 + beta) I_B I_E = 0.2625 m A using K V L in collector loop - V_CC = I_C R_C + V_CE + I_E R_E V_CE = V_CC - I_C R_C - I_E R_E V_CE = 10 - 0.2604 * 8 - 0.2625 * 4 V_CE = 6.8668 V \r\n I_E = I_E Q = 2 m A I_B = I_E/1 + beta = 2 m A/1 + 125 = 0.01587 m A I_C = beta I_B = 1.9841 m A using K V L in Base loop - V_BB = I_B R_B + V_BE + I_E R_E 0.01587 R_B + 2 R_E = V_BB - V_BE = 3 - 0.7 0.01587 R_B + 2 R_E = 2.3 ----(1) using K V L in collector loop - V_CC = I_C R_C + V_CE + I_E R_E 12 = 1.9841 R_C + 4 + 2 R_E