Question

A sample of an ideal gas at 1.00 atm and a volume of 1.86 L was placed in a weighted balloon and dropped into the ocean. As the sample descended, the water pressure compressed the balloon and reduced its volume. When the pressure had increased to 65.0 atm, what was the volume of the sample? Assume that the temperature was held constant.​

Answer 1

PV = nRT this is the ideal gas constant value

at constant T above equation can be written as a

P1V1 = P2V2

P1 = 1.0 atm, V1 = 1.86 L

P2 = 65.0 atm, V2 = ?

1.0 x 1.86 = 65.0 x V2

V2 = 1.86 / 65.0

V2 = 0.0286L