Kiting during a storm. The legend that Benjamin
Franklin flew a kite as a storm approached is only a legend — he
was neither stupid nor suicidal. Suppose a kite string of radius
2.11 mm extends directly upward by 0.815 km and is coated with a
0.520 mm layer of water having resistivity 178 ?·m. If the
potential difference between the two ends of the string is 168 MV,
what is the current through the water layer? The danger is not this
current but the chance that the string draws a lightning strike,
which can have a current as large as 500 000 A (way beyond just
being lethal).
area of cross section
A = 3.14*(((2.11+0.52)*10^-3)^2-(2.11*10^-3)^2) = 7.74*10^-6 m^2
resistance of the wire R = rho*l/A
R = 178*0.815*10^3/7.74*10^-6
R = 18.74*10^9 ohm
current through the wire is
i = v/R
i = 168*10^6/18.74*10^9
i = 8.96 mA = 8.96*10^-3 A
Kiting during a storm. The legend that Benjamin Franklin flew a kite as a storm approached...