expected number in 10 squared cm =1000*10 =10000
and standard deviation =sqrt(10000) =100
for normal distribution z score =(X-μ)/σx |
probability = | P(X>10030) | = | P(Z>0.3)= | 1-P(Z<0.3)= | 1-0.6179= | 0.382 |
Suppose that the number of asbestos particles in a sample of 1 squared centimeter of dust...
Asbestos fibers in a dust sample are identified by an electron microscope after sample preparation. Suppose that the number of fibers is a Poisson random variable and the mean number of fibers per square centimeter of surface dust is 100. A sample of 800 square centimeters of dust is analyzed. Assume that a particular grid cell under the microscope represents 1/160,000 of the sample. (a) What is the probability that at least one fiber is visible in the grid cell?...
Suppose the number of invasive carp in one mile of river is distributed according to the Poisson distribution with a mean of 8 carp per mile. Use the normal approximation to the Poisson to find the probability of fewer than 70 carp being found in a 10 mile stretch of river. First, without the continuity correction: Second, with the continuity correction
Additional Problem 6. Suppose that a sample of n 120 tires of the same type are obtained at random from an ongoing production process in which 5% of all such tires produced are defective. Let X denote the number of defective tires in a sample. Compute the probability that at least 6 tires in a sample are defective by (a) using the exact distribution of X; (b) using the normal approximation with continuity correction; c) using the Poisson approximation. Additional...
1. In a particular facility, 60% of students are men and 40% are women. In a random sample of 50 students what is the probability that more than half are women? Let the random variable X = number of women in the sample. Assume X has the binomial distribution with n = 50 and p = 0.4. What is the expected value and variance of the random variable X? (6 points) In a random sample of 50 students what is...
Suppose that 12% of the population of the U.S. is left-handed. If a random sample of 130 people from the U.S. is chosen, approximate the probability that at most 14 are left-handed. Use the normal approximation to the binomial with a correction for continuity. Round your answer to at least three decimal places. Do not round any intermediate steps. (If necessary, consult a list of formulas.) x 5 ?
OD Suppose that 12% of the population of the U.S. is left-handed. If a random sample of 130 people from the U.S. is chosen, approximate the probability that at most 14 are left-handed. Use the normal approximation to the binomial with a correction for continuity. Round your answer to at least three decimal places. Do not round any intermediate steps. (If necessary, consult a list of formulas.)
suppose that 16% of the population of the US is left-handed. If a random sample of 240 people from the US is chosen, approximate The probability that more than 39 or left-handed. Use the normal approximation to the by no meal with the correction for continually. Round your answer to that lease three decimal places do not round any intermediate step
1 2 Suppose that 10% of the population of the U.S. is left-handed. If a random sample of 155 people from the U.S. is chosen, approximate the probability that at least 16 are left-handed. Use the normal approximation to the binomial with a correction for continuity. Round your answer to at least three decimal places. Do not round any intermediate steps. (If necessary, consult a list of formulas) Х $ 2 e
please round at least three decimals Suppose that 10% of the population of the U.S. is left-handed. If a random sample of 155 people from the U.S. is chosen, approximate the probability that al least 16 are left-handed. Use the normal approximation to the binomial with a correction for continuity. Round your answer to at least three decimal places. Do not round any intermediate steps. (If necessary, consult a list of formulas) 0 X ?
A binomially distributed random variable has a probability of success equal to 0.72. For random samples of size 5200. Use the Normal approximation to calculate the probability that more than 3800 successes are observed. Don't forget to show continuity correction. Round to 4 decimals