Question

2. A light ray enters a rectangular block of plastic at an angle θ 1=43.0° and emerges at an angle θ,-81.00, as shown. Find d 43° 81°
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Answer #1

apply snell's law on first surface

1 *sin 43 = n *sin ( phi)

apply snell's law on 2nd surface

n *sin ( 90 - phi) = sin 81  

n *cos ( phi) = sin 81

divide both

tan ( phi ) = sin ( 43) /sin ( 81)

solve for phi

we got  

phi = 34.625 degree

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