Question

A King in ancient times agreed to reward the inventor of chess with one grain of wheat on the first of the 64 squares of a chess board. On the second square the King would place two grains of wheat, on the third square, four grains of wheat, and on the fourth square eight grains of wheat. If the amount of wheat is doubled in this way on each of the remaining squares, how many grains of wheat should be placed on square 21? Also find the total number of grains of wheat on the board at this time and their total weight in pounds (Assume that each grain of wheat weighs 1/7000 pound.)

Answer 1

The number of grains in the first square is 1 The number of grains in the second square is a The number of grains in the fund square is a d = 22 The number of grains in the fasth square is 2.22 =23 220 similarly the number of grains in the ath square is . qu- .. number of grains in the 21st square is gellan The total number of grains in these al squares = at å ta et 24.:.+ 2200 2-1 he know that some of Geometric series is azartart.-tart = a(h) The Given that each par dagen weighs 1/2 round 1. height of all grains = (21) = 299.59 rands మా Scanned with CamScanner