Question

Chapter 21, Problem 030 In the figure particles 1 and 2 are fixed in place on an x axis, at a separation of L - 8.10 cm. Their charges are q = +e and 42 --27. Particle 3 with charge 43 - +3e is to be placed on the line between particles 1 and 2, so that they produce a net electrostatic force F.net on it. (a) At what coordinate should particle 3 be placed to minimize the magnitude of that force? (b) What is that minimum magnitude? (a) Number Units (b) Number Units Click if you would like to Show Work for this question: Open Show Work

Answer 1

We will be solving this problem using the simple formula for force experienced by a charge particle due to other charged particle.

$F_i_j = \frac{k|q_i| |q_j |}{r_i_j}$

54 11 2 {(N-T) 23 ten 3 人で w L-u V21 E n 3 M X # Substitute value of L 8.10 x 102 2.025 X10 61 4 x = 2.025 x 102 m

6) Fz, net k qa 92 X2 (-u) 2 - 9x109 X -19 3 x l-bxo 1.6x10-19 24 x 1.6x104 + (2.025x102) ² (4x - x)² [ : x -10 11 43.2 x 10 - 15 0.39 x 10 -19 43.2 x 10 36.91 x 10-4 -10 432x10 [ 0.39 x 1015 -15 1. ITI x 10 os 10 43.2 X10 1.56) X)0 10"] 67. #352 X10 F3, net 67. 4352 -25 XD Z

Therefore,

a) The Coordinate for the particle 3 to minimize force is X= 2.025 cm or 2.025 x 10-2 m .

b) The Minimum magnitude of Force = 67.4352 x 10-25 N.

Hope this Helps!!