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μs = 0.595, and the kinetic friction coefficient is μk = 0.459. The combined mass of...

μs = 0.595, and the kinetic friction coefficient is μk = 0.459. The combined mass of the sled and its load is m = 261 kg. The ropes are separated by an angle φ = 23°, and they make an angle θ = 30.8° with the horizontal. Assuming both ropes pull equally hard, what is the minimum rope tension required to get the sled moving?

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Answer #1

Fy=0

mg-N=0

mg=N

Fx=0

2Tcos(30.8)= fs = \mus N=\mus mg

T= \mus mg/2cos(30.8) = 0.595 x261x9.8/2 con(30.8)

T =886 N

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