Question

Problem 3: A solenoid that has 50 turns per centimeter has a radius of 3 cm. There is a single circular loop with radius of 2 cm in the very center of the solenoid. The axes of both the solenoid and the loop are the exact same. The current through the solenoid varies with time based on the formula below beginning at a time we will define to be t = 0. What is the emf generated in the single loop at the time t = 2.57 where T = 30 s? (10 points) I(t) = 5(1 - e-"/") (this formula is in SI units)

Answer 1

Given! A solenoid with 50 terny n = 50 turns 0.01) cm r = 3 un m = 0.03 so, aument through solenoid will make it on electromagnet, with B = Mon I At the same time, ń also ia device a colourid for capturing flux de NBA mwa But since we are asked for the emf of circular loop of radius razum, and single turn, N=1 Scanned with Camsafinend be a will in terms terms of circular T loop.

Mons. T. It) T() г (1 – 7 ) д. N в А - 1x вхт в т. 4 в. м, пт км, , s(- et/-) ко, В. : Вт*- - Моля пт - - * ) 1 (мо теп- - А) o, p. E1 - /e) ее - ә Е - - эЕ 2 - ka, (- ) Scanned with CamScanner

&=-k ( Že the to find at t = 2.52, e = 30 2 . So, { k ė ) olunu E: Моя пт- = 417 xlo? x 500 x 5 x 17 x (0.033 = 8.9xios & a=305 - 2 .5 63 - 8.9 x 10 x 30 E = -2,430 emf so, the generated in the loop wop is 6= 2.43 v Aus Ics Scanned with CamScanner

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