Question

4. A 50-cm long dipole is excited by a sinusoidally varying current with an amplitude lo = 5 A. Determine the time average power radiated by the dipole if the oscillating frequency (a) 1 MHz, (b) 300 MHz

Answer 1

- we have a dipole antenna of 50cm long. ca) This antenna is excited by a carnent with biezwency f: IMHz and amplitude lo = 5 A. Hence the wall length is = 3x108 Txis 1. At this a = 300m condition, is a hertsion pipole so antenna this as so the redicted power is calculated Prod = 407) 0 ( = 400*xs*aloy = 49869.6044) (1.6667 x 10 9)? = (986 9.60476.97789 X 100) | Pad = 0.0274 W]

Hence power dipole rodioted by hertsion frequency is 0.02746 with IMHz 20) This on tenna is excited by a current with frequency f = 300 MHz and emplitude to = 5A Hence - wal as Hence the wallelength À - - 3x108 300x106 À = im At this condition, Ž= o.se 750 so so 1. this antenna is a holl ware Dipole. the rodioted power is. Porod = 36.610 = 36,649" Prod = 915 W

Hence dipole power with radiated by I MHz frequency helf is wake 915 w
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