mass of block A=>ma=3.6/9.8=0.37 kg
mass of block B=>mb=5.4/9.8=0.55 kg
coefficient of friction =0.25
step;2
now we find the force applied on block B
force F=0.25(0.37+0.55)*9.8=2.254 N
Block A in the figure weighs 3.6 N, and block B weighs 5.4 N. Block A...
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