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Block A in the figure weighs 3.6 N, and block B we
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Answer #1

mass of block A=>ma=3.6/9.8=0.37 kg

mass of block B=>mb=5.4/9.8=0.55 kg

coefficient of friction =0.25

step;2

now we find the force applied on block B

force F=0.25(0.37+0.55)*9.8=2.254 N

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