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M Review At the instant A = 50, the boys center of mass G is momentarily at rest. (Figure 1) Determine his speed when A = 85

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75 26 32.2 2T = mat E E= ma mat cos O = l=10ft M5 at 75 cos0 32.2 At = 32.2 coso = man mv2 mg sine 2T- > 2T - 75sino 75 v2 32> ds = ldo > ds = 10 de 85 32.2 cos0 x 10 do ニ 50° 85 Vdv = 322 coso do 50 85 2.7 sino 322 %3D 50 22 sin 85-sin 50) v- 644(0-

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