Question

a. Question 4 [15 points) A cannon of mass 40 kg resting in the chamber of a projectile launcher is projected straight upwards, giving the cannon an initial velocity of 30.0 m/s. Assuming the cannon travels in a region free from non-conservative forces: How much work is done by the projectile launcher on the cannon? [2 points) b. How much work must be done to stop the cannon when it is at a 2 points) height 60% of its total vertical displacement? If a stopping force of 600 N is applied on the cannon over 5 m while 4 points) in flight, what would be the difference in peak heights obtained? d. If instead, the stopping force of 600 N is applied on the cannon in part [7 points) (a) for 1.5 seconds, what would be the difference in peak heights? c.

Answer 1

ca) Work done change in ke (40kg) (2001532 wa mmoea Ç 18000 5 at height of 0.6ohman PE = 0.60 kfmax Oo6x18000 J KE Kemax PE 0.418000 5 Work done Дke : 0- (0-4 X18000) Two - 72005 without stopping force, 18000 = (40)(98) (H) H = 45.9m 60005 with force, = 18000 140X96) (seph) + (600*) h = 38.1m sha H-h 7.63M CScanned with CamScanner

ਮਿS, 6004 140x9:8) a, - 24.8 m/82 40 hos (30x 75) - (24.5x1054) 17.4m So using then VE 30- (9,6) 30- (24,8 x115) = -7.2 m/s So peale height is before 1.5*, v - 12 = dad is de 30²= 2 (-24.8) (h) h = 18.14m sh 45.9 - 18.14 27-8m CScanned with Camstariner