Question

Help these athletes out.

A) Determine the vertical impulse required for a 49 kg high jumper to clear a height of 6 ft 8 in. Assume that the high jumper's center of mass starts at 3 ft 6 in and that his center of mass just clears the bar. (positive up)
(include units with answer)

B) A golfer playing on a level course hits a 43.0 g golf ball that leaves the tee at a 25° upward angle and hits the ground 171 m away. What was the magnitude of the impulse given to the ball? (neglect air resistance)
(include units with answer)

Answer 1

2.032m 1 682sin 16946 m 0.9652m V 1.3ft sin 1.0668m impuke - tedt V Impulse P omuni I fex d t = dap2 mcVf-vi) uust clear means, Vf=0 Vip up2– 2xgx (2.032 -1.0663) . Up2 = 2x9.818.9652 1. uf V; 24.35169m5! Impulse -mvi=4q+4.35169 - 213.2329 NS UUUU b) impulse = Pf-li ANN ALAN pf = mcucosai - USINGI) Piz m Cerose i tusinco) ff-Pia ~2 musings Range - Ucos@x7 - Usox lusing R =CR5inzo ។
Kp
a=fR9/anzo 171x9.81 = 66:795m5" V sinso Imparse a Pf-Piz -2musings --24 0.043x46.795 XSMZS impulse -1.7007
the magnitude =1.7007 Ns