Question

Using the table of standard formation enthalpies that you'll find under the ALEKS Data tab, calculate the reaction enthalpy of this reaction under standard conditions: Fe, 0(s)+3 CO(9—12 Fe(s)+3 CO (9) Round your answer to the nearest kJ.

Answer 1

We Know that 4HM nx 4H (products)- nx 4 Creaetom)

The naaction- Fe, O3 (s)+3co() 2 Fes)3co, Ca) :.4 11 Jrom able AH oFe03() -824-2 KJ/mo! 4Ho COC2)-10.5 KJfmof 4Hj o FeCs) 4 H o Co )-393.5 KJ/mol O K/mot

Aconding 42x (co-ng 5sx 4g (co)] + 3x X o+80-5)-[-8242+ (-331.5) -824-2-331.5 1180.5 1155 7 - J180.5 24.8 K o - |180.5 +| 55.7 225 KwoL -25 KJ/mot. An . 4HM