Question

Calculate how much KOH you will need to weigh out to make 250 mL of a 0.2M KOH solution. How much potassium hydrogen phthalate (molar mass 204.23 g/mol) do you need to weigh out if you want to use 20.00 mL of your standard 0.2000 M KOH solution to titrate the potassium hydrogen phthalate sample? Note: potassium hydrogen phthalate has ONE hydrogen that reacts with KOH. We often use KHP as our "simplified formula" for potassium hydrogen phthalate rather than writing out the entire molecular formula

Answer 1

(niven 2.50 m L a0.2 M KOH Salatlan . ko H= (250X10-3 Χ Ο.z)/Troly 50o xi0-4 mole 0.0S mole NO· mmoler Weight 엄 k0H Hena, we need KoH t Wei ght ur 50ml 염 a 0.2M-Ko H . Num be needed mumbe moles of KoH Because, it山given that KHphas Gnehydhogen thot eact with IKoH moles кон -(20x10-3 LX 0.2000 mali) so, Numbe, 연 mole 형 KHPmeeded = 4x10-3 4 XIo-3 moley (niver), Mola, mass KmP= 204,238/mol ReQuired Weight KHPmoles x molas, may (4x10.3 x 204.23 ) = 816.92 x10-39 816.92×1D" 8 Pertaddium Hence need hydhogen phthalati to wegr Su