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(Reference Using the reagents listed in the table below, show how to bring out the following transformations: A B (Specify th
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step A : ef

step B : b

In this reaction an alkyne is converted to a ketone.

The first step is the deprotonation and reaction with an alkyl halide. Here, the alkyne reacts with NaNH2 which is a strong base to get deprotonated. Iodine atom leaves with the pair of electrons from ethyl iodide followed by nucleophilic attack to the carbanion.

The second step is the hydration of alkyne. Here, H2O, H2SO4 and HgSO4 is the hydrating agent and reacts with alkyne to form ketone.

So the reagents in the first step are NaNH2 and CH3CH2I and in the second step is H2O, H2SO4, HgSO4.

NaNH2 CH₃ CH2 0 But-r-yne butyn-i-ide Hex-3-yne 2 H₂O, H2504, HgSO4 hex-3-yne 3-hexanone

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