Question

3) A square wire loop with 2.00 m sides is perpendicular to a uniform magnetic field as shown in the figure. The loop contains an ideal battery with emf ε-20.0V. Ifthe magnitude of the field varies with time according to B-0.0420-0.870, with B in teslas and f in seconds, what ure the (a) (10 points) the net emf in the circuit and (Show your work and explain your answer. (b) (10 points) the direction of the (oet) current around the loop? (Show your work and explain your answer.)

A square wire loop with 2.00m sides is perpendicular to a uniform magnetic field as shown in the figure. The loop contains an ideal battery with emf=20.0V. If the magnitude of the field varies with time according to B=0.0420-0.870t , with B in teslas and t in seconds, what are the:

A. Net emf in the circuit (show your work and explain your answer)

B. And the direction of the (net) current around the loop? (shoe your work and explain your answer)

Answer 1

a )

given

L = 2.00 m

emf = 20.0 V

B = 0.0420 - 0.870 t

area A = 0.5 X L²

A = 0.5 X 2² = 2 m²

dB / dt = - 0.87

using equation E = - N A ( dB / dt )

E = - 1 X 2 X ( -0.87 )

E = 1.74 V

so the Net emf in the circuit is E_net = 20 + 1.74

E_net = 21.74 Volts

b )

the direction of the (net) current around the loop is ANTICLOCKWISE direction