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Calculate and use the molar volume of a gas under ndard temperature and pressure conditions Question...
Zinc reacts with hydrochloric acid according to the reaction equation Zn(s)+2HCl(aq)⟶ZnCl2(aq)+H2(g)Zn(s)+2HCl(aq)⟶ZnCl2(aq)+H2(g) How many milliliters of 2.00 M HCl(aq)2.00 M HCl(aq) are required to react with 8.55 g Zn(s)?
Zinc will react with hydrochloric acid to give hydrogen in accord with the equation given below. How many mL of a 3M solution HCL are required to react with 10.0 g of zinc? ( Molar mass of Zn=(65.41 g/mol ) Zn(s) + 2 HCL(aq) ====>ZnCl2(aq) + H2 (g)
Calculate the volume of hydrogen produced at 2.50 atm and 22°C by the reaction of 25.4 g of zinc with excess hydrochloric acid according the balanced chemical equation below. Zn (s) + 2 HCl (aq) ® ZnCl2 (aq) + H2 (g)
Zinc reacts with hydrochloric acid according to the reaction equation shown. Zn(s) + 2 HCl(aq) — ZnCl2 (aq) + H2(g) How many milliliters of 5.00 M HCl(aq) are required to react with 4.95 g of an ore containing 23.0% Zn(s) by mass? volume:
When 0.40 g of impure zinc reacted with excess hydrochloric acid, 127mL of hydrogen gas were collected over water at 10 degrees C at a total pressure of 737.77 Torr. The vapor pressure of water at 10 degrees C is 9.21 Torr. The reaction in question is: Zn (s) + 2HCl (aq) --> ZnCl2 (aq) + H2 (aq) A.) what amount (in grams) of H2 gas was collected? B.) what is the percentage of purity of the zinc, assuming that...
Zinc reacts with hydrochloric acid according to the reaction equation shown. Zn(s)+2HCl(aq)⟶ZnCl2(aq)+H2(g) How many milliliters of 5.00 M HCl(aq) are required to react with 2.65 g of an ore containing 26.0 % Zn(s) by mass? volume: mL
QUESTION 8 The density of a gas is 1.2 g/L at STP. What is its molar mass? a. 30 g/mol b. 27 g/mol c. 46 g/mol d. 18 g/mol e. 29 g/mol QUESTION 4 What is the oxidation half-reaction for the reaction of zinc with hydrochloric acid? Zn(s) + 2H+ (aq) + 2C1"(aq) → Zn2+(aq) + 2Cl(aq) + H2(8) O a. 2H +(aq) + 2e (aq) → H 2(3)+261 (aq) b. 2H +(aq) + 2e - → H2(g) OC. Zn(...
In the flask in which the balloon was inflated fully – assume here that the flask was filled with HCl to the top) – estimate the final volume of the balloon. You may assume that the pressure was equal to 1 Atm. Rxn. 1: 7 g Zn Rxn. 2: 3.27 g Zn Rxn. 3: 1.31 g Zn Description Zinc and hydrochloric acid react to form hydrogen gas and aqueous zinc chloride. Zn(s) + 2 HCl(aq) → ZnCl2(aq) + H2(g) The...
2. How many liters of hydrogen (Hz) gas can be produced from the reaction of 0.750 g of zinc (Zn) metal with excess HCl at STP. Zn (s) + 2 HCl(aq) + H2(g) + ZnCl2 (aq)
Q2 part1. Hydrogen gas can be readily prepared by reacting zinc metal with hydrochloric acid: Zn(s) + 2HCl(aq) → ZnCl2(aq) + H2(g) A sample of zinc metal was decomposed in hydrochloric acid and the hydrogen gas was collected over water. The volume of gas collected is 0.798 L at 25oC and a total pressure of 735 torr. How many grams of zinc were decomposed assuming there is an excess of hydrochloric acid? [Hint: the vapor pressure of water at 25oC...