F is the buoyancy force which is the weight of the displaced water minus the weight of the ball itself
F = (pw - pfoam ) *V*g
Where, V = (4/3)*pi*r^3 = (4/3)*pi*(d/2)^3 = (1/6)pi*d^3
F = (1*10^3 - 95)*(1/6)*pi*d^3*9.8
554 = 4643.8d^3
d = cuberoot(554/4643.8)
= 0.49 m
A child playing in a swimming pool realizes that it is easy to push a small...
A child playing in a swimming pool realizes that it is easy to push a small inflated ball under the surface of the water whereas a large ball requires a lot of force. The child happens to have a styrofoam ball (the shape of the ball will not distort when it is forced under the surface), which he forces under the surface of the water. If the child needs to supply 554 N to totally 1.000 x 103 kg/m2, the...
A child playing in a swimming pool realizes that it is easy to push a small inflated ball under the surface of the water whereas a large ball requires a lot of force. The child happens to have a styrofoam ball (the shape of the ball will not distort when it is forced under the surface), which he forces under the surface of the water. If the child needs to supply 635 N to totally submerge the ball, calculate the...
please help!!!
A child playing in a swimming pool realizes that it is easy to pash a small inflated ball under the surface of the water whereas large ball requires a lot of force. The child happens to have a styrofoam ball (he shape of the ball will not distort when it is forced under the surface), which he forces under the surface of the water. If the child needs to supply 581 N to totally submerge the ball,calculate the...
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3. If you've ever played with an inflated ball of any type while swimming, you've probably noticed that if a ball is already floating on the surface of the water, it's easy to push it down a few centimeters. But then it's harder to push it the next few cm down, and so on, until the ball is completely submerged-the last few cm are the hardest! submerged. 1-2 sentences, no equations or math. b) Suppose, once the ball is completely...