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Given f(x) = x2 – 7 defined over the interval [2.5, 2.75]. Using Bisection method, the approximated root after the third iter

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2 f(na) = (2.640625) -7 20 f(3) fins) 23 ng f(13)f(na)ko 4 f(24) The #th appronimation de retna 2 2.65625 +2.640625 up 2 2.64Therefore the 8th approximation is ng my tno 2 = 2.646484375 +2.64453125 2 !! 2.6455078125 The fore the approximating roof wi

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Given f(x) = x2 – 7 defined over the interval [2.5, 2.75]. Using Bisection method, the...
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