A rectangular loop of wire is placed next to a straight wire, as shown in the...

Question

Question

Answer 1

Answer #1

r = 0.03 m

R = 3 + 5 = 8 cm = 0.08 m

L = length of wire = 10 cm = 0.10 m

F₁ = Force on the upper side

F₁ = ( $\mu$ /4 $\pi$ ) (2 i²L /r) = (10^-7) (2 (3.5)² (0.10) /(0.03)) = 81.7 x 10^-7 N upward

F₂ = Force on the lower side

F₂ = ( $\mu$ /4 $\pi$ ) (2 i²L /R) = (10^-7) (2 (3.5)² (0.10) /(0.08)) = 30.625 x 10^-7 N downward

Net force is given as

F_net = F₁ - F₂ = 81.7 x 10^-7 - 30.625 x 10^-7 = 51.075 x 10^-7 N = 5.1 x 10^-6 N

Answer 2

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