Question

What is the magnitude of the current in the 20 resistor? 102 40V 20 22 60 V 102 0 1.0 A O 2.0 A O 1.5A O 0.50 A

Answer 1

respective current passes as per the below Let the circuit lor I 60V 3 9012 Lov ③ Applying keachoffey cannend low cat point I, = Iqt Zz o low voltage to the loop o Applying Kerchoffig 40- (10) I, - (20) I 2 = 0 on 1101, + 20 I2 = 40 Applying kinchoffig voltage load to the loop -(20) I2 + (10) 13 +60=0 as Iz= I, - Iz from egno -(20)/2 + (10)(1,-12) +60=0 - - 201, +102, - 1022 760=0 or 101, -30 I2 = -60

subtracting equation & from equation 101, +2012=40 101 - 3012 = -60 - + + 50 I2 = 100 1 I 2 = 2 A Hence, resistor 2 Lg= 24 spagnitude of curnent in 2022 option -
comment - the current in the 20 ohm resistor is 2A.