In an ethylene glycol-water solution, there are 20.0 g ethylene glycol for every 80.0 g water....
A solution of ethylene glycol in water at 20.0°C has a mass percent of 8.25% of ethylene glycol with a density of 1.0087 g/mL. The freezing point depression constant for water (which you can assume is the solvent for all solutions) is K1.86°C kg/mol and the boiling point elevation constant is Kb the following: 0.512°C kg/mol. The density of neat water at 20.0°C is 0.9982 g/ml. Answer 1. What is the molarity of the solution? 2. What is the molality...
A solution of ethylene glycol in water at 20 degrees celsius has a mass percent of 9.78% of ethylene glycol with a density of 1.0108 g/mL. The freezing point depression constant for water (solvent for all solutions) is Kf=-1.86 percent celsius kg/mol and the boiling point elevation constant is Kb=0.512 degrees celsius kg/mol. The density of neat water at 20.0 degrees celsius is 0.9982 g/mL. Answer the following: 1. What is the molarity of the solution? 2. What is the...
An ethylene glycol solution contains 27.6 g of ethylene glycol (C2H6O2) in 92.0 mL of water. (Assume a density of 1.00 g/mL for water.) Determine the freezing point of the solution. Determine the boiling point of the solution.
An ethylene glycol solution contains 24.4 g of ethylene glycol (C2H6O2) in 85.4 mL of water. (Assume a density of 1.00 g/mL for water.) 1.Determine the freezing point of the solution. 2.Determine the boiling point of the solution.
An ethylene glycol solution contains 14.2 g of ethylene glycol (C2H6O2) in 83.4 mL of water. A.Calculate the freezing point of the solution. (Assume a density of 1.00 g/mL for water.) Express your answer in degrees Celsius using three significant figures. B. Calculate the boiling point of the solution. Express your answer in degrees Celsius using two decimal places.
An ethylene glycol contains 22.2 g of ethylene glycol (C_2H_6O_2) in 82.4 mL of water Calculate the freezing point of the solution. (Assume a density of 1.00 g/mL for water.) Calculate the boiling point of the solution.
An ethylene glycol solution contains 30.0g of ethylene glycol (C2H6O2) in 95.6mL of water. (Assume a density of 1.00 g/mL for water.) 1.Determine the freezing point of the solution. Express you answer in degrees Celsius 2.Determine the boiling point of the solution. Express you answer in degrees Celsius.
What volume of ethylene glycol (HOCH2CH2OH, density = 1.12 g mL-1) must be added to 20.0 L of 112 of water (Kf = 1.86 °C kg mol-1) to produce a solution that freezes at -10 °C?
How many liters of the antifreeze ethylene glycol [CH2(OH)CH2(OH)] would you add to a car radiator containing 5.50 L of water if the coldest winter temperature in your area is −20.0°C? Calculate the boiling point of this water-ethylene glycol mixture. (The density of ethylene glycol is 1.11 g/mL.) What is the volume of antifreeze? L What is the boiling point of the solution?
An automobile antifreeze mixture is made by mixing equal volumes of ethylene glycol (d=1.114 g/mL; M= 62.07 g/mol) and water (d=1.00 g/mL) at 20°C. The density of the mixture is 1.070 g/mL. Express the concentration of ethylene glycol as (a) volume percent I % v/v (b) mass percent % w/w (c) molarity м (d) molality (e) mole fraction