The magnetic field over a certain range is 01.76896e-18 given by B Bi+By 3, where B...
Please answer and explain 5,6, and 7. It's a multistep question! 005 (part 1 of 3) 10.0 points The magnetic field over a certain range is given by B = B, i + B, , where Be = 7 T and By = 1 T. An electron moves into the field with a velocity v = vzî+v, Î+vzk, where Vr = 3 m/s, Vy = 9 m/s and v, = 1 m/s. The charge on the electron is -1.602 x...
-5 m/s and v 3 m/s. The field is given by B- Bi+ Bi where B 2 T and By 4T. The charge on the electron is -1.6 x 10-19 C. What force F is exerted on the electron by the magnetic field? A) B) F-4(j-,51+k ) F 8(i+j+k ) D) F 3.2 x 1019 (6i-3j +5k) E) F 1.28 x 1018 (j-i k)
Plz answer all questions (20 pts/5 pt. each) As shown in the figure, the magnetic field over a certain range is given by B- B,k, where B,-0.5T.A proton moves into the magnetic field with a velocity - i+v,j+v,k, where v,-1x 10 m/s, By 3 x 10s m/s, and v, 3x10s m/s. The charge ofthe proton is 160x10" C,and the mass ofthe proton is 1.67 x 10 kg Here t.J.k are unit vectors in the x, y and z directions, respectively...
Crossed electric and magnetic fields are established over a certain region. The magnetic field is 0.6000 T vertically downward. The electric field is 2.000 x 106 V/m horizontally east. An electron, traveling horizontally northward, experiences zero resultant force from these fields and so continues in a straight line. What is the electron's speed? m/s
Chapter 28, Problem 005 An electron moves through a uniform magnetic field given by B = B: +(4.93 B,) . At a particular instant, the electron has velocity V = (1.85 / +4.13 ) m/s and the magnetic force acting on it is (3.74 x 10-19) K N. Find Bx. Number Units the tolerance is +/-6%
An electron moves through a uniform magnetic field given by B = Bxi+(3.74Bx)j. At a particular instant, the electron has velocity V =(2.88i+4.37j)m/s and the magnetic force acting on it is (2.74x10^-19)k N. Find Bx An electron moves through a uniform magnetic field given by B 3.74 B . At a articular instant, the electron has velocit y 2.88 , -37 m/s and the magnetic orce acting on t is 7 ·r Linda Number Units
030 (part 1 of 2) 10.0 points A proton in a cyclotron is moving with a speed of 3.27 x 10 m/s in a circle of radius 0.704 m. 1.67 x 10-27 kg is the mass of the pro- ton, and 1.60218 x 10-19 C is its fundamental charge. What is the magnitude of the force exerted on the proton by the magnetic field of the cyclotron? Answer in units of N. 031 (part 2 of 2) 10.0 points What...
An electron in a vacuum is first accelerated by a voltage of 31200 V and then enters a region in which there is a uniform magnetic field of 0.253 T at right angles to the direction of the electron’s motion. The mass of the electron is 9.11 × 10−31 kg and its charge is 1.60218 × 10−19 C. What is the magnitude of the force on the electron due to the magnetic field? Answer in units of N.
#1 This print-out should have 14 questions. Multiple-choice questions may continue on the next column or page - find all choices before answering 001 10.0 points A particle with charge q and mass m has speed v. At t = 0, the particle is moving along the negative r axis in the plane perpendicular to the magnetic field B, which points in the positive : direction in the figure below. 10-"c. What is the i component of the force ex-...
An electron moves with velocity v ⃗ =(6.8i−5.3j)× 10 4 m/s in a magnetic field B ⃗ =(−0.64i+0.57j)T . Part A Determine the x-component of the force on the electron. Express your answer using two significant figures. Fx = N Part B Determine the y-component of the force on the electron. Express your answer using two significant figures. Fy = N Part C Determine the z-component of the force on the electron. Express your answer using two significant figures....