application in broad band communications
Given, the rate of arrival of packets = 85 packets/sec.
Time required by each packet is 8 millisecs
ie = 1/8ms
= 125 packets/ sec
Therefor traffic intensity
= 85/125 = 0.68
The given system is stable since the departure rate is greater than arrival rate.
3. The estimated waiting time of packets in the system so
The estimated waiting time in the queue
4.The estimated number of packets in the queue
The estimated number of packets in the system
5. The minimum packet processing time which will make system unstable is when
6. The system is blocking now, the probability of 40 or more packets in the system is this is the blocking probability of the system.
application in broad band communications less than or equal to 0.6ms (that is 600 usec). (2...