Question

Consider a pendulum of length l and a bob of mass m at its end, moving...

Consider a pendulum of length l and a bob of mass m at its end, moving through oil with theta decreasing. The massive bob undergoes small oscillations, but the oil retards the bob's motion with a resistive force proportional to the speed with Fres=2m(sqrt(g/ l))*(l(theta)).The bob is initially pulled back at t=0 with theta=alpha and (theta)'=0. Find the angular displacement theta and velocity theta' as a function of time.

2 0
Add a comment Improve this question Transcribed image text
Know the answer?
Add Answer to:
Consider a pendulum of length l and a bob of mass m at its end, moving...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • The length of a simple pendulum is 0.75 m and the mass of the particle (the...

    The length of a simple pendulum is 0.75 m and the mass of the particle (the "bob") at the end of the cable is 0.33 kg. The pendulum is pulled away from its equilibrium position by an angle of 9.1° and released from rest. Assume that friction can be neglected and that the resulting oscillatory motion is simple harmonic motion. (a) What is the angular frequency of the motion? (b) Using the position of the bob at its lowest point...

  • A certain simple pendulum consists of a small 750.0 ? bob that swings on the end...

    A certain simple pendulum consists of a small 750.0 ? bob that swings on the end of a 25.0 ?? string. The small amplitude of the oscillations of this pendulum decays to half its original value after 45.0 oscillations. The angular position of the pendulum as a function of time, ?(?), can be expressed as follows. ?(?) = ??0 ? − ??/2m cos(? ′ ? + ?) ??0 is the original angular amplitude. ? is the time, and ? is...

  • A simple pendulum with mass m = 2.3 kg and length L = 2.62 m hangs...

    A simple pendulum with mass m = 2.3 kg and length L = 2.62 m hangs from the ceiling. It is pulled back to an small angle of θ = 9.2° from the vertical and released at t = 0. 1) What is the period of oscillation? 2) What is the magnitude of the force on the pendulum bob perpendicular to the string at t=0? 3) What is the maximum speed of the pendulum? 4) What is the angular displacement...

  • A simple pendulum with mass m = 2.1 kg and length L = 2.79 m hangs...

    A simple pendulum with mass m = 2.1 kg and length L = 2.79 m hangs from the ceiling. It is pulled back to a small angle of θ = 11.5° from the vertical and released at t = 0. 1) What is the period of oscillation? 2) What is the magnitude of the force on the pendulum bob perpendicular to the string at t=0? 3) What is the maximum speed of the pendulum? 4) What is the angular displacement...

  • Chapter 10, Problem 45 GO The length of a simple pendulum is 0.75 m and the...

    Chapter 10, Problem 45 GO The length of a simple pendulum is 0.75 m and the mass of the particle (the "bob") at the end of the cable is 0.28 kg. The pendulum is pulled away from its equilibrium position by an angle of 9.1° and released from rest. Assume that friction can be neglected and that the resulting oscillatory motion is simple harmonic motion. (a) what is the angular frequency of the motion? (b) Using the position of the...

  • Chapter 10, Problem 45 GO The length of a simple pendulum is o.70 m and the...

    Chapter 10, Problem 45 GO The length of a simple pendulum is o.70 m and the mass of pendulum is pulled away from its equilibrium position by an angle of 8.8° and released from rest. Assume that friction can be neglected and that the resulting oscillatory motion is simple harmonic motion. (a) What is the angular frequency of the motion? (b) Using the position of the bob at its lowest point as the reference level, determine the total mechanical energy...

  • A simple pendulum with mass m = 1.8 kg and length L = 2.77 m hangs...

    A simple pendulum with mass m = 1.8 kg and length L = 2.77 m hangs from the ceiling. It is pulled back to an small angle of θ = 9° from the vertical and released at t = 0. 1) What is the period of oscillation? Answer= 3.34 s 2) What is the magnitude of the force on the pendulum bob perpendicular to the string at t=0? Answer= 2.76 N 3) What is the maximum speed of the pendulum?...

  • he length of a simple pendulum is 0.65 m and the mass of the particle (the...

    he length of a simple pendulum is 0.65 m and the mass of the particle (the “bob”) at the end of the cable is 0.20 kg. The pendulum is pulled away from its equilibrium position by an angle of 7.7° and released from rest. Assume that friction can be neglected and that the resulting oscillatory motion is simple harmonic motion. (a) What is the angular frequency of the motion? (b) Using the position of the bob at its lowest point...

  • A simple pendulum with mass m = 2.1 kg and length L = 2.3 m hangs...

    A simple pendulum with mass m = 2.1 kg and length L = 2.3 m hangs from the ceiling. It is pulled back to an small angle of θ = 11.9° from the vertical and released at t = 0. 4)What is the angular displacement at t = 3.56 s? (give the answer as a negative angle if the angle is to the left of the vertical) 6)What is the magnitude of the radial acceleration as the pendulum passes through...

  • The motion of a pendulum bob with mass m is governed by the equation mL0" (t) + mg sin θ (t)-0 where L is the lengt...

    The motion of a pendulum bob with mass m is governed by the equation mL0" (t) + mg sin θ (t)-0 where L is the length of the pendulum arm, g 3 and θ is the angle (in radians) between the pendulum arm and the vertical. Suppose L 16 ft and the bob is set in motion with (0 1 and 0' (0)--3. Find the second degree Taylor polynomial P2(t) that approximates the angular position θ(t) of the bob near...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT