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3.1.7 Remark. Trivially, for any R:A → B, we have dom(R) C A and ran(R) CB (give a quick proof of each of these inclusions).

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3.1.4 B , we have dom (R) SA and show that for any R:A ran (R1 SB. ket RAB. If possible let 7 x t dom(R) which is not in A. T

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