12. What value of c make the function f(x) = (x2 – 3x when x > 2 continuous when x = 2? 14x + 2c when x < 2 a)-5 b)-3 c) 0 d) 1
Solve this problem using the two-phase method. What special case do you observe? Max Zz4X1-2X2+X3 X1+2X2+X3 3 2X1-3X2+6X3 100 X1,X2,X3>0
1. Given the piece-wise function, 3x if x < 0 f(x)=x+1 if 0 < x 52 :- 2)2 if x>2 Evaluate f (__); f(0); f (); f(5)
Evaluate the piecewise defined function at the indicated values (x2 f(x) if x -1 6x if 1 < x s 1 = -1 if x > 1 f(-3) (- 3 2 f(-1) f(0) = f(30) =
Consider the random variable X whose probability density function is given by k/x3 if x>r fx(x) = otherwise Suppose that r=5.2. Find the value of k that makes fx(x) a valid probability density function.
Find all values x= a where the function is discontinuous. 7 if x <4 f(x) = x- 9 if 4 sxs7 7 if x>7 O A. a=7 O B. a=9 OC. a=4 OD. Nowhere
(a) For what value of x does f(x) = g(x)? (b) For which values of x is f(x) >g(x)? For every x in the interval f(x)>g(x). (Type your answer in interval notation.) In parts (a) and (b), use the given figure. (a) Solve the equation: f(x) = g(x). (b) Solve the inequality f(x) > g(x). у y = g(x) y = f(xN (-9,7)
2.5.9. The random variable X has a cumulative distribution function for xo , for xsO . for r>0 F(x) = z? 1 +x2 Find the probability density function of X.
2.5.9. The random variable X has a cumulative distribution function for xo , for xsO . for r>0 F(x) = z? 1 +x2 Find the probability density function of X.
How to solve it?
Let F =< -2, x, y2 >. Find S Ss curlF.nds, where S is the paraboloid z = x2 + y?, OSz54.