Question

any help would be great!

A car is moving along a straight road. At time t seconds, the position of the car (in feet) is s(t) = 51. Find the average velocity of the car over the time intervals given below. (a) t = 11 to t= 11.1 seconds (b) t = 11 tot = 11.01 seconds (c) t = 11 to t = 11.001 seconds (a) The average velocity of the car over the time interval from t = 11 to t= 11.1 seconds moving along a straight road is D (Simplify your answer. Round to one decimal place as needed.) (b) The average velocity of the car over the time interval from t = 11 to t= 11.01 seconds moving along a straight road is (Simplify your answer. Round to two decimal places as needed.) (c) The average velocity of the car over the time interval from t= 11 tot 11.001 seconds moving along a straight road is (Simplify your answer. Round to three decimal places as needed.)

Answer 1

The solution is given in the image...

ten average velocity = I sdt { tz-t, = J szedt t₂ - 7 Zz-t, = {( 33 - ') 7-71 anti-li to tz = 1). I (11-1)} -(11)31 8. 36063) = { H J = $x36005) 111.)-11 3 = 61,0.516 ł 61005 5) ty=1l. to te = 11:01 - 3-633_60505 -گراه الام 1 = > x 60 sos 0.01 11.01-11 I c) 0-363 60505 7,211 to 72 = 11.ool (11.001) 3-(11131 "110001-12 0.001 = 605.1