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Draw the structure(s) of all of the alkene isomers, C H12, that contain an unbranched chain and that have EIZ isomers. • Cons

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Cotiz The possible isomers are ) Нc = CH – CH2 - сн,- сна-сна 2) сня - сH = CH – CH2 – СН2-СН3 3) сH, — сн, - сн =CH– сна- сн7) CH3 – CH – Chy – CH = CH Cala 8) CH₂=CH CH - CH₂ - CH₂ CH3 7) C1-CH=CH-CH2-CH3 Сн, (0) Ste Szchis CHR 10) HC сиз – CH = CHAmong the possible isomers Orly first three isomers are not branch. In that three isomers only and s 3rd isomer exhibit E-2 i

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