Question

Does sigma (3n^2-n+1)/sqrt(n^7+2n^2+5) converge or diverge using limit comparison test.

Does

sigma (3n^2-n+1)/sqrt(n^7+2n^2+5) converge or diverge using limit comparison test.

0 0
Add a comment Improve this question Transcribed image text
Answer #1

0 to e no comparing with 5 an E 31 - nt nan l+212 +5 Here an= 3n2_nt1 choose bna 0312 - am onza an = n2 [ 3 - 1 2 + 1 2 ] 2eus an - nua bo lm (3-1 + 1 he] nao - 3-1 tto Mitte - 3-oto. Ttoto hawa n = 3 = 3 (20, 0), By Limit comparchion series eitheryou have any doubt Dont forget Matting. comment Thankiy me, i will replay. you

Add a comment
Know the answer?
Add Answer to:
Does sigma (3n^2-n+1)/sqrt(n^7+2n^2+5) converge or diverge using limit comparison test.
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
Active Questions
ADVERTISEMENT