What is the formula weight for iron(III) oxide, in amu?

Question

Question

Answer 1

Answer #1

iron(III) oxide

Fe2O3

Atomic mass of Fe = 55.84 amu

atomic mass of oxygen = 16 amu

formula weight of Fe2O3 = 2*55.84 +3*16

= 111.68 + 48 = 159.68 amu

Answer 2

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