Question

Complete the nuclear equation

253 293Es +; He → in + ? 10

? =

1.) $_{105}^{248}\textrm{Es}$

2.) $_{103}^{252}\textrm{Md}$

3.) $_{101}^{257}\textrm{Es}$

4.) $_{101}^{256}\textrm{Md}$

5.) $_{97}^{249}\textrm{Bk}$

6.) $_{102}^{254}\textrm{Bk}$

7.) none of the above

Answer 1

answer:   4) 256,101 Md

according to law of mass action , the sum of the mass of reactants .must be equals to products.

253 , 99 Es + 4,2 He ----> 1,0 n + 256,101 Md