Jacob wants to estimate the mean length of time (in minutes) all College students spend reading online journal articles. To determine this estimate, he took a random sample of 15 people and obtained the following results: 40, 110, 56, 20, 15, 10, 82, 60, 90, 118, 35, 25, 5, 65, 30. The population of times is normally distributed. Find a point estimate for the population mean. Round off your answer to the nearest whole number.
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Jacob wants to estimate the mean length of time (in minutes) all College students spend reading online journal articles. To determine this estimate, he took a random sample of 15 people and obtained the following results: 40, 110, 56, 20, 15, 10, 82, 60,
Matthew wants to estimate the mean length of time (in minutes) all Senior High students spend reading online news articles. To determine this estimate, he took a random sample of 15 people and obtained the following results: 40, 110, 56, 20, 15, 10, 82, 60, 90, 118, 35, 25, 5, 65, 30. The population of times is normally distributed. Construct the 95% confidence interval for the population mean length of reading time. Type the endpoints of the interval separated by...
Mark wants to estimate the mean length of time (in minutes) all Middle School students spend reading online books. To determine this estimate, he took a random sample of 15 people and obtained the following results: 40, 110, 56, 20, 15, 10, 82, 60, 90, 118, 35, 25, 5, 65, 30. The population of times is normally distributed. What is the margin of error at the 95% confidence level if the population standard deviation is 8 minutes? Round off you...
a published wants to estimate the mean length of time all adults spend reading news papers. to determine the estimate the publisher take a random number sample of 15 people and obtained the results below. from past studies, the publisher assumes õ is 1.7 minutes and that the population of times normally distributed. 6, 10,10,11,11,10,6,8,7,7,8,7,8,12,9. construct the 90% and 99% confidence intervals for the population mean,
- publisher wants to estimate the mean length of time in minutes) all adults spend reading newspapers. To determine this estimate the publisher takes a random sample of 15 people and obtain the results below. From past studies, the bisher assumes als 1.9 minutes and that the population of times is normally distributed 10 12 10 7 10 11 6 7 6 Construct the 90% and 99% confidence intervals for the population mean. Which interval is wider convenient, use technology...
10 A publisher wants to estimate the mean length of time (in minutes) all adults spend reading newspapers. To determine this estimate the publisher takes a random sample of 15 people and obtains the results below. From past studies, the publisher assumes o is 23 minutes and that the population of times is normally distributed 12 9 10 7 9 8 7 12 12 6 11 9 9 Construct the 90% and 99% confidence intervals for the population mean. Which...
To estimate the mean score ?μ of those who took the Medical College Admission Test on your campus, you will obtain the scores of an SRS of students. From published information you know that the scores are approximately Normal with standard deviation about 6.2. You want your sample mean ?¯ to estimate ?μ with an error of no more than 1.4 point in either direction. (a) What standard deviation must ?¯ have so that 99.7% of all samples give an...
An admissions director wants to estimate the mean age of all students enrolled at a college. The estimate must be within 1.5 years of the population mean. Assume the population of ages is normally distributed. (a) Determine the minimum sample size required to construct a 90% confidence interval for the population mean. Assume the population standard deviation is 1.6 years. (b) The sample mean is 20 years of age. Using the minimum sample size with a 90% level of confidence,...