Question

2.0 EXAMPLEI : The following data were obtained for a separation using a 0.5 mm id, 10 meter open tubular column: Retention time (min) Peak base width (min) Methane Cyclohexane 8.0 0.65 Methylcyclohexane 8.17 0.72 Toluene 10.2 0.95 a)Draw the chromatogram and label the peaks b) Calculate the number of theoriticla plate for each compound (N) and palte height (H) c) Calculate the capacity factor for each compound d) the resolution between tow consequent peak R, e) Calculate the length of the column needed to separate cyclohexane and methylcyclohexane at a resolution of 1.6. D) is the system suitable with accepted parameters ?

Answer 1

A ven that Given that, Internal diameter, daoismm, length, L = com.. Number of theoritical plates, : 5.545 ( no. of Plates be (N) = 5.50 where, N- no. of plates, (a) tR = Retention time, wha peak width at half height The following data is Retention Peak I no. of plates 1. time Base width Methane L 200 cyclohexane 0.66 839.95 Methyl cyclohexane 8'17 0.72 713.97 . 10.2 Toluene 0.95 639.92 734,04

. . ang. no. of plates for the column=731, (6) Plate heights to a Plate height equivalent theoritical plates (H) - where he length of column (mm) MV Na no. of theoritical plates. i ; Ho 0.85X1000 731 H = 1.16 mm / (c) Resolution between the peaks cyclo 1 hexane & Methylcyclohexane; 1 Resolution when peak width at base given as is R = 2 tez-tR. Whit whe where, tra relation time of second peak, tRi= relation time of first peak, wb = Peak width at base of ist peak, Wb2 = Peak width at base of and Peak,

Here, *R,= 8.0; *R2=8.17; wb,=0.65; Wb2=0.720 Substate all the values in é i-e 8.17 - 8.00 R; 21. 0.65 to.72 .: R = 0.2481] :: Resolution (R) - 0.2481 z please like, Thank you.